C Program to find total number of arguments passed

C Program to find total number of arguments passed

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C supports variable of arguments. But there is no language provided way for finding out total number of arguments passed. So lets write to find total number of arguments passed. User has to handle this in one of the following ways:
1) By passing first argument as count of arguments.
2) By passing last argument as NULL (or 0).
3) Using some printf (or scanf) like mechanism where first argument has placeholders for rest of the arguments.

Following is an example that uses first argument arg_count to hold count of other arguments.

C Program to find total number of arguments passed :

#include <stdarg.h>
#include <stdio.h>

// this function returns minimum of integer numbers passed.  First
// argument is count of numbers.
int min(int arg_count, ...)
{
  int i;
  int min, a;

  // va_list is a type to hold information about variable arguments
  va_list ap;

  // va_start must be called before accessing variable argument list
  va_start(ap, arg_count);

  // Now arguments can be accessed one by one using va_arg macro
  // Initialize min as first argument in list  
  min = va_arg(ap, int);

  // traverse rest of the arguments to find out minimum
  for(i = 2; i <= arg_count; i++) {
    if((a = va_arg(ap, int)) < min)
      min = a;
  }  

  //va_end should be executed before the function returns whenever
  // va_start has been previously used in that function
  va_end(ap);  

  return min;
}

int main()
{
   int count = 5;

   // Find minimum of 5 numbers: (12, 67, 6, 7, 100)
   printf("Minimum value is %d", min(count, 12, 67, 6, 7, 100));
   getchar();
   return 0;
}

 

Output:
Minimum value is 6

Let us know if you face any issues with the above C program in comments below.

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